11x^2-29x-240=0

Solution for 11x^2-29x-240=0 equation:

11x^2-29x-240=0

a = 11; b = -29; c = -240;
Δ = b2-4ac
Δ = -292-4·11·(-240)
Δ = 11401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{11401}}{2*11}=\frac{29-\sqrt{11401}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{11401}}{2*11}=\frac{29+\sqrt{11401}}{22}
$